Jqgrid.info_dialog Is Not A Function, Do I Have To Call Extend?
Solution 1:
jqGrid defines not only "standard" methods, which can be used as $("#grid").jqGrid("methodName", ...) or $("#grid").methodName(...), but some other methods. The "standard" methods will be registered under $.fn.jqGrid.methodName (like $.fn.jqGrid.editGridRow function for example) and, if no $.jgrid.no_legacy_api = true; is specified before $.jgrid.no_legacy_api = true;, then under $.fn.methodName too.
In other words there are exist only global object $.fn.jqGrid or $.fn, which contains the "standard" jqGrid methods.
Some other list of methods will be registered under $.jgrid instead of $.fn.jqGrid or $.fn. info_dialog is an example of such method. Thus one should use $.jgrid.info_dialog, $.jgrid.jqID, $.jgrid.htmlEncode, $.jgrid.randId and so on to use such methods. The most of the methods don't require to initialize this (like $.jgrid.randId()$.jgrid.jqID("some.text")), but some methods require that this is initialized to DOM of the grid (the empty <table> used to generate the grid).
For example, you can use
$grid.jqGrid("navButtonAdd", "#pager", {
caption: "Test",
onClickButton: function () {
$.jgrid.info_dialog.call(this,
"Warning with two buttons",
"Click the `test` button",
"Close",
{
buttons: [
{
text: "\"text\" button",
id: "buttid",
onClick: function() {
alert("click...");
}
}
]
}
);
}
});
See https://jsfiddle.net/OlegKi/xLrbdspo/. I use in the demo free jqGrid fork, which I develop, but the same works with the retro version 4.6 of jqGrid, which you use.
The final remark. If you know the syntax of TypeScript, that you can find in free-jqgrid.d.ts answers on many of questions like the usage of info_dialog. The methods and properties of $.jgrid are described here (inclusive info_dialog). You will find here additionally some methods $.fmatter, $.jqm, $.jqDnR and $.unformat which are the part of jqGrid in the same way like $.jgrid.
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