How To Use Firebug's Monitor(fn)?

I read the Firebug documentation about the Command Line API. Wrote monitor(functionName) in the command editor and pressed Ctrl+Enter. I can't see anything happening... May be my u

Solution 1:

Work fine for me...

Check out the example i made at http://fiddle.jshell.net/gaby/LbCYn/show/

Open the console and put monitor(toBeMonitored);. Now each time you click the button it will put in the console that the method was executed..