Find Items In Javascript Object Array Where One Of The Properties Does Not Match Items In Another Array

Say I have two arrays, one of objects, one simple: var objArray = [{id:1,name:'fred'},{id:2,name:'john'},{id:3,name:'jane'},{id:4,name:'pete'}] var simpleArray = [1,3] I want to

Solution 1:

You could try this one:

var results = [];

objArray.filter(function(item){
    if(simpleArray.indexOf(item.id)>-1)
        results.push(item);
})

Please try the following snippet:

functionCustomer(id, name){
  this.id=id;
  this.name=name;
};

this.Customer.prototype.toString = function(){
  return"[id: "+this.id+" name: "+this.name+"]";
}

var objArray = [ newCustomer(1,'fred'), newCustomer(2,'john'), newCustomer(3,'jane'), newCustomer(4,'pete')];

var simpleArray = [1,3];

var results = [];

objArray.filter(function(item){
   
    if(simpleArray.indexOf(item.id)>-1)
        results.push(item);
});

document.write(results)

Solution 2:

@Christos' answer is good for many cases; however, if the simple array gets very large then the performance of that solution will degrade considerably (because it is doing a linear search instead of a constant-time lookup). Here is a solution that will perform well even when the simple array is very large.

functionfilterByMissingProp(objects, values, propertyName) {
  var lookupTable = values.reduce(function(memo, value) {
    memo[value] = true;
    return memo;
  }, {});
  return objects.filter(function(object) {
    return !(object[propertyName] in lookupTable);
  });
}

var result = filterByMissingProp(objArray, simpleArray, 'id');
result; // => [ {id:2, name:"john"}, {id:4, name:"pete"} ]