Dynamic Dhtmlx Organization Chart Using Php And Json
i have a problem. i don't really understand how should i output this correctly using loops. Table Data: | Name | Position | |:-------------------|------------
Solution 1:
functionloop(array$parents, $need)
{
$children = [];
$isLast = $need === 1;
$lastKey = count($parents) - 1;
foreach ($parentsas$key => $parent) {
$id = $parent === 3 ? $key + 1 : 1;
$children[] = $child = "$parent.$id";
$comma = $isLast && $key === $lastKey ? '' : ',';
echo"{ID:$child,Parent:$parent}$comma" . "<br/>";
}
$need--;
if ($need) {
return loop($children, $need);
}
return$children;
}
loop([3, 3], 4);
Solution 2:
i fix my problem here's my answer on my question:
SQL:
$sql = mysqli_query($conn,"SELECT * FROM `brgy_official_detail` bod
INNER JOIN resident_detail rd ON rd.res_ID = bod.res_ID
LEFT JOIN ref_suffixname rs ON rs.suffix_ID = rd.suffix_ID
LEFT JOIN ref_position rp ON rp.position_ID = bod.commitee_assignID
WHERE visibility = 1 AND position_Name LIKE 'Barangay Official%'");
count the query content:
$count_official = mysqli_num_rows($sql);
Declaring temp array:
$name = array();
$position_Name = array();
$official_img = array();
Fetch the data and save to array:
while($official_data = mysqli_fetch_array($sql)){
$suffix = $official_data['suffix'];
if ($suffix == "N/A") {
$suffix = "";
}
else{
$suffix = $official_data['suffix'];
}
$name[] = $official_data['res_fName'].' '.$official_data['res_mName'].' '.$official_data['res_lName'].' '.$suffix;
$position_Name[] = $official_data['position_Name'];
if (isset($official_data['res_Img'])) {
$z = $official_data['res_Img'];
$official_img[] = "data:image/jpeg;base64,".base64_encode($z);
}
else{
$official_img[] = "../../Img/Icon/logo.png";
}
}
and then i improve qskane answer:
function loop(array $parents, $need,$index,$name,$position_Name,$official_img)
{
$children= [];
$isLast=$need===1;
$lastKey= count($parents) -1;
foreach ($parentsas$key=>$parent) {
$p_name=$name[$index];
$pos_Name=$position_Name[$index];
$img=$official_img[$index];
$id=$parent===3?$key+1 : 1;
$children[] =$child="$parent.$id";
$comma=$isLast&&$key===$lastKey? '' : ',';
echo "{
\"id\":\"$child\",
\"text\": \"$pos_Name\",
\"title\": \"$p_name\",
\"width\": 350,
\"img\": \"$img\",
\"parent\":\"$parent\"
}$comma";
}
$index++;
$need--;
if ($need) {
return loop($children, $need,$index,$name,$position_Name,$official_img);
}
return$children;
}
$index=0;
loop([3], $count_official,$index,$name,$position_Name,$official_img);
?>
];
Post a Comment for "Dynamic Dhtmlx Organization Chart Using Php And Json"